A can complete a piece of work in 8 hours, b can complete in 10 hours and c in 12 hours. if a,b, c start the work together but a laves after 2 hours. find the time taken by b and c to complete the remaining work.
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Answered by
5
A can do the work in 8 hrs
B can do the work in 10 hrs
c can do the work in 12 hrs
in 1 hr A does =1/8 part
in 1 hr B does =1/10 part
in 1 hr C does =1/12 part
together in 1 hr they does =(1/8+1/10+1/12)
= (15+12+10/120)
= 37/120
after working for 2 hrs A left
work done = (37/120×2)=37/60 part
B and C can do =(37/120-1/8) part
=(37-15/120) part
=22/120=11/60
work remaining = (1- 37/120)=113/120
work. time
37/120. 1
113/120. x
x=1/37/120×113/120
= 1/37×120/37×113/120
=113/1369
= 12whole 43/113 hrs
B can do the work in 10 hrs
c can do the work in 12 hrs
in 1 hr A does =1/8 part
in 1 hr B does =1/10 part
in 1 hr C does =1/12 part
together in 1 hr they does =(1/8+1/10+1/12)
= (15+12+10/120)
= 37/120
after working for 2 hrs A left
work done = (37/120×2)=37/60 part
B and C can do =(37/120-1/8) part
=(37-15/120) part
=22/120=11/60
work remaining = (1- 37/120)=113/120
work. time
37/120. 1
113/120. x
x=1/37/120×113/120
= 1/37×120/37×113/120
=113/1369
= 12whole 43/113 hrs
Answered by
16
Answer:
Step-by-step explanation:
A can do a work in 8 days
B in 10 days
C in 12 days
LCM for 8,10,12 is 120=total work
A's 1 day work will be 120/8=15
similarly B's 1 day work=12 and C's 1 day work =10
total work =A+B+C=15+10+12=37/hr
for 2hrs=37*2=74(completed)
120-74=46(incomplete)
it is to be completed by B+C
B+C's 1 day work=12+10=22
therefore 46/22=2 1/11
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