Question

A can complete a piece of work on 6 days and B can complete in 12 days.if A started that work and worked for 3 days then B joined A. For how many days B worked

Answer 1

Answer:

This is a example to your question

you can consider this to solve

A can do a piece of work in 16 days

B can do a piece of work in 12 days

B can do a piece of work in 1 day=1/12

(A+B) can finish in 1

day=(1/16+1/12)=(3+4/48)=7/48

(A+B) can finish 7/48 work in 1day

Now 2 days work done by A=1/16×2=1/8

Remaining work after 2 days=1–1/8=7/8

Remaining work done by (A+B)=(48/7×7/8)=6

Required time to finish the work=6+2=8 days

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Answer 2

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