A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quiets 10 days before the project is completed, in how many days will the project will be completed?
Answers
Answer:
A can complete a project in 20 days. So, A will complete 1/20th of the project in a day.
B can complete a project in 30 days. So, B will complete 1/30th of the project in a day.
Let the total number of days taken to complete the project be x days.
B worked for all x days. However, A worked for (x−10) days because A quits 10 days before the project is completed.
In a day, A completes 1/20th of the project.
Therefore, A would have completed (x−10)th/20 of the project in (x - 10) days.
In a day, B completes 1/30th of the project.
Therefore, B would have completed x/30th of the project in x days.
∴(x−10)/20+x/30=1 Once we solve this equation, we get x=18.
It will take 18 days to complete the whole project.A can complete a project in 20 days. So, A will complete 1/20th of the project in a day.
B can complete a project in 30 days. So, B will complete 1/30th of the project in a day.
Let the total number of days taken to complete the project be x days.
B worked for all x days. However, A worked for (x−10) days because A quits 10 days before the project is completed.
In a day, A completes 1/20th of the project.
Therefore, A would have completed (x−10)th/20 of the project in (x - 10) days.
In a day, B completes 1/30th of the project.
Therefore, B would have completed x/30th of the project in x days.
∴(x−10)/20+x/30=1 Once we solve this equation, we get x=18.
It will take 18 days to complete the whole project.
Step-by-step explanation:
A+B=30 days
A+B=20/30=2/3(since they worked together 20 days)
remaining work=1/3
A-60 days
