Question

A can complete a project in 20 days and B in 16 days. They worked together for 5 days and then
A leaves. In how many days will B finish the remaining project?​

Answer 1

Step-by-step explanation:

Given A can do the work in 20 days and B can do it 16 days.

Then work done by A in one day = $\frac{1}{20}$

And, work by B in one day = $\frac{1}{16}$

Then, the work done by A & B in one day = $\frac{1}{20} + \frac{1}{16}$

= $\frac{9}{80}$

A & B done 5 days together then work done in A & B in 5 days = $\frac{9}{80} \times 5$

Then friction of work left = 1 -$\frac{9}{16}$=$\frac{7}{16}$

Then B can do $\frac{7}{16}$work = $\frac{7}{16} \times \frac{16}{1}$= 7 days.

Hope this answer helps you out.

Answer 2

✨ Required Answer =>

If both are working together:

1/20 + 1/30 = 1/12,

which means A and B working together will complete the project in 12 days.

So,

total of 25+2 = 27 days.

Hope it will helps ✌

$:)$