A can complete a work in 10 days , B in 12 days , and C in 15 days . All of them begin the work together , but A had to leave the work after 2 days of the start and B , 3 days before the completion of the work . How long did the work last?
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Answer:
7 days
Step-by-step explanation:
A work in 10 days
B work in 12 days
C work in 15 days
total work = LCM of 10, 12, 15
= 60
A's efficiency= 6
B's efficiency= 5
C's efficiency= 4
2days work= 15*2=30
left work= 60-30= 30
last 3 days only work C.
last 3 days work= 12
left work= 30-12= 18
18/9= 2days after B left the work..
total days to completed the work= 2+2+3=7 days
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