Question

‘A’ can complete a work in 20 days while B is 25% more efficient than ‘A’. B worked for 6 days and left, remaining work is completed by ‘C’ in 15 days. Find in how many days ‘C’ can complete the whole work alone? (a) 27 days (b) 21 days (c) 18 days (d) 24 days (e) 30 days

Answer 1

Answer:

Efficiency of A = 100

Efficiency of B = 125

= 4:5

Therefore Ratio of time taken is 5:4

Here 5 corresponds to 20 days so 4 will equals 16 days.

Total work will be 80

B alone completed 30 work in 6 days.

So remaining work is 50.

Therefore efficiency of c can be found out. Which equals 10/3.

So time taken by C equals

80*(3/10)

= 24 days

Step-by-step explanation:

Answer 2

Answer:

B can complete the work alone= 20 × 4 /5 = 16 days

efficiency of A=100

B=125

So ratio=4:5

Let C alone can complete work in ‘x’ days

6 /16 + 15/ = 1

15 / = 10 /16

x = (15 × 16) /10 = 24 days