Question

A can complete A work in 24days,B in 32days and C in 64 days.they start together.A works for 6days and leaves and B leaves 6days before the work is finished.In how many days was the work finished?

Answer 1

Answer:

20 days

Step-by-step explanation:

let Total work = LCM(24,32,64) = 192 units

their efficiencies:

A = 192÷24 = 8 units/day B = 192÷32 = 6

C = 192÷64 = 3

together they can do = 8+6+3 = 17 units/day

(A+B+C)'s 6 days work = 6 ×17 = 102 units

last 6 days work is done by C = 6×3 = 18 units

work done by B&C together= 192-(102+18)

= 72 units

time taken B&C together = 72/(6+3) = 8 days

work was finished in

= 6 + 6 + 8 = 20 days