A can complete a work in 64 days. B is 60% more efficient than A. A and C can complete work in 12(4/5)days. then B and C can complete the work in how many days
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B is 60p more efficient
ie ratio of efficiency of B and A is 16:10
time is inversely proportional to efficiency
ie B completes the same work in 64×10/16=40 days
total work is 64×10=40×16 as total work is efficiency×days to complete the work.
A and C completes the work in 64/5 days
efficiency of A and C is 64×10×5/64=50
but efficiency of A is 10 (explained above)
ie efficiency of C is 50-10=40.
now efficiency of B and C is 16+40=56
then time taken bu B and C= 40×16/56=40×2/7=80/7=11³/⁷ days(ans)
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