Question

A can contain a mixture of two liquids a and b in the ratio 7 : 5 when 9 liters of mixture are drawn of and the can is filled with b the ratio a and b becomes 7 : 9

Answer 1

Answer:

Step-by-step explanation:

First of all, the wording of the question is a bit unclear. It needs to specify that 9 litres were removed and 9 litres was added back. "can is filled" is not sufficient because we do not know whether the can was full initially.

Say initial volume of mix is V1. After you remove 9 litres, the concentration of liquid A remains 7/12 and volume of the mix is (V1 - 9).

After you add back liquid B, the concentration of A becomes 7/16 and volume comes back to V1.

Ci*Vi = Cf*Vf

(7/12)*(V1 - 9) = (7/16)*V1

(V1 - 9)/V1 = 3/4

9 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*9 = 36 litres.

7/12 of the initial mixture was liquid A so liquid A was (7/12)*36 = 21 litres.

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