Question

A can contains 50 litres of milk. 10 litres of this milk is taken out and replaced with water. This process is repeated twice. Find the amount of remaining milk in the mixture?

Answer 1

Answer:

20 litre is water and 30 litre of milk is left

Answer 2

There is 32 liters of milk is left.

Step-by-step explanation:

Since we have given that

Quantity of milk = 50 liters

Quantity of milk is taken out = 10 liters

And the process is repeated twice.

So, it becomes,

$=(1-\dfrac{b}{a})^n$

Here, a is the initial quantity

b is the quantity removed

n is the number of times it happens.

So,Amount of remaining milk in the mixture is given by

$(1-\dfrac{10}{50})^2\\\\\=(1-\dfrac{1}{5})^2\\\\=(\dfrac{5-1}{5})^2\\\\=(\dfrac{4}{5})^2\\\\=\dfrac{16}{25}$

So, the amount of remaining milk in the mixture would be

$\dfrac{16}{25}\times 50\\\\=16\times 2\\\\=32\ liters$

Hence, there is 32 liters of milk is left.

# learn more:

A container contains 90 litres of milk from this container 9 litres milk was taken out and replaced with water and this process was repeated two times the quantity of milk in the mixture is

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