Math, asked by stkabirdin8200, 11 months ago

A can contains 80% of pure milk .What part of mixture should be removed and substituted with water such that the resulting mixture would contains milk and water in ratio of 3:2

Answers

Answered by prathapaanaghambikap
0

Answer:

1/4 of total milk

Step-by-step explanation:

Answered by morrisonnikhil
0

Answer: is 25% of the mixture

Step-by-step explanation:

Let's consider 100% mixture of milk and water, then by method of alligation, considering only portion of milk, you'll be mixing solution of 80% milk and solution of 0% milk (considering pure water) to get 60% milk (from question stating that milk and water ratio as 3:2), you should remove 1/4 (=25%) part of total mixture and substitute it with water to get milk and water ratio of 3:2.

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