A can contains 80% of pure milk .What part of mixture should be removed and substituted with water such that the resulting mixture would contains milk and water in ratio of 3:2
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Answer:
1/4 of total milk
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Answer: is 25% of the mixture
Step-by-step explanation:
Let's consider 100% mixture of milk and water, then by method of alligation, considering only portion of milk, you'll be mixing solution of 80% milk and solution of 0% milk (considering pure water) to get 60% milk (from question stating that milk and water ratio as 3:2), you should remove 1/4 (=25%) part of total mixture and substitute it with water to get milk and water ratio of 3:2.
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