A can contains a mixture of two liquids A and B
in the ratio 7: 5. When 9 litres of mixture are
drawn oft and the can is filled with B, the ratio
of A and B becomes 7: 9. How many litres of
liquid A was contained by the can initially?
a) 10
b) 20
c) 21
d) 25
Answers
Answered by
12
Step-by-step explanation:
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively.
Quantity of A in mixture left=(7x−
12
7
×9)=(7x−
4
21
) litres
Quantity of B in mixture left =(5x−
12
5
×9)=(5x−
4
15
) litres
Now,
5x−
4
15
+9
7x−
4
21
=
9
7
=>
20x+21
28x−21
=
9
7
=>252x−189=140x+147
=>x=3
Thus, the can contains 21 litres of A.
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