Math, asked by anianveshanianvesh, 1 year ago

A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

Answers

Answered by surya7972
5
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<b><font face=copper black size =4 color=purple>

Solution

Let the can initially contain 7x litre and 5x litre of mixture A and B respectively.
<b><font face=copper black size =4 color=red>
Thus out of 12x litre of total mixture, 9 litre were taken out. 
<b><font face=copper black size =4 color=blue>
Quantity of A in mix. left
<b><font face=copper black size =4 color=green>
= 7x - 9/12x * 7x
<b><font face=copper black size =4 color=orange>
= 28x-21 / 4 litre
<b><font face=copper black size =4 color=purple>
Quantity of B in mix. left
<b><font face=copper black size =4 color=black>
= 5x- 9/12x*5x 
<b><font face=copper black size =4 color=red>
= 20x-15 / 4 litre
<b><font face=copper black size =4 color=blue>
Therefore ratio 
<b><font face=copper black size =4 color=red>
7:9
<b><font face=copper black size =4 color=green>
or x = 3
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