Question

A can contains a mixture of two liquids a and b is the ratio 7 5

Answer 1

let A = 7x & B = 5x

total mixture = 7x+5x=12x

after 9 litre of mixture are drawn off remaining misture = 12x-9

after filling can with B:

A = (12x-9) * 7/12= 28x-21

B = {(12x-9)* 5/12}+9= 20x+21

So, (28x-21)/(20x+21)= 7/9

by solving above equation, we get

x=3

So liquid A was contained by the can initially = 7x = 7*3 = 21

Mark as brainliest

Answer 2

Answer:

Explanation:

Suppose, The can contain 12 litres i.e= (7x+5x)

Now,

A's quantity that is left is= 7x-7/12 and since we know that 9 litres have been taken out from the mixture, 7/12*9=21/4, so

A's actual quantity left=7x-21/4

Same with B's quantity= 5x-5/12*9= 5x-15/4, also, 9 litres are added to B, so,

B's actual quantity left= (5x-15/4)+9

In the question, there final ratios after adding and drawing out are already given, i.e. = 7:9 or 7/9

So we can clearly say that

(7x-21/4) / (5x-15/4)+9 = 7 / 9

Now, by solving the equation, we get,

252x-189 = 140x+147

112x          = 336

x               = 3

We need to find A's quantity before the mixture was disturbed, and that was 7x:5x

A=7x

A=7*3

a=21 Litres