A can dig a hole in 40 days and B can do it in 60 days. Along with C, they did the job in 12 days only. In how many days can C alone dig two such holes? (A) 24 days B) 48 days (C) 10 days (D) 8 days
Answers
Answer:
the answer of this question is (C) 10 days.
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Answer:
C can along dig two such holes in 48 days.
Step-by-step explanation:
Given,
A can dig a hole in 40 days
B can dig a hole in 60 days
Together A, B and C can dig a hole in 12 days
Total work duration of A, B and C to dig a hole = HCF of 40, 60 and 12
= 120
Efficiency of A = 120 / 40
= 3
Efficiency of B = 120 / 60
= 2
Total Efficiency of A + B + C = 120 / 12
= 10
Efficiency of C = (Total Efficiency of A+B+C) - Efficiency of A - Efficiency of B
= 10 - 2 - 3
= 5
No. of days C can alone dig 2 holes = (120 × 2 ) /5
= 48 days