Question

A can do 1/3 of the tank work in 5 days and B can do 2/5
of the work in 10 days,
In how many days both A and B together can do work?
​

Answer 1

Answer:

A's 5 days work+ B's 7 days work + C's 13 days work =1

∴ (A+B)

′

s 5 days work + (B+C)

′

s 2 days work + C's 11 days work = 1

∴

12

5

+

16

2

+ C's 11 days work=1

∴ C's 11 days work=1−(

12

5

+

16

2

) =

24

11

∴ C's 1 days work =(

24

11

×

11

1

) =

24

1

∴ C alone can finish the work in 24 days.

Answer 2

Answer:

15 days

Step-by-step explanation:

5 days add 10 days that how much