A can do 1/6 of the work in 5 days and B can do 2/5 of the work in 8 days. In how many days can both A and B together do the work?
Answers
Step-by-step explanation:
A does 1/6th of the work in 5 days
therefore in one day he does (5×1/6) th of the work = 5/6 th of the work
B does 2/5th of the work in 8 days.
therefore in one day he does (8×2/5) th of the work = 16/5 of the work
Therefore in 1 day they both can do (5/6+16/5) th of the work. i.e (121/30)
Thus both can do the work in 1÷121/30 = 30/121 days
Answer:
12 days.
Step-by-step explanation:
work done by A in 5 days = 1/6 th part
work done by A in 1 day = (1/6)/5 = 1/30 th part
work done by B in 8 days = 2/5 th part
work done by B in 1 day = (2/5)/8 = 2/40 = 1/20 th part
Total work done by A and B in 1 day = (1/30) + (1/20) th part
= (20 + 30)/(20×30) = 50/600 = 1/12 th part.
so, the days needed by A and B to complete the total work = 1/(1/12) = 12days.