Math, asked by sanskarkhandelwal29, 10 months ago

A can do 2/3 of a certain work in 16 days and B can do 1/4 of the same work in 3 days .In how many days can both finish the work, working together?​

Answers

Answered by sumant73
19

Answer:

2/3 of a work is done by A = 16 days

1 of a work is done by A = 16/2/3

= 16×3/2

= 24 days

1/4 of a work is done by B = 3 days

1 of certain work is done by B = 3/1/4

= 3 ×4/1

= 12 days

work done by A in 1 day = 1/24

work done by B in 1 day = 1/12

work done by both (A + B) in 1 day = ( 1/24 + 1/12)

= ( 1 + 2/24)

= (3/24)

= 1/8 = 8 days

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