Math, asked by vernekarvignesh21, 7 months ago

A can do 25% of a work in 4 days and B can do one third of the same work in 4 days. C can comp.
work in the same time as A and B would take working together. If all the three work together, how
it take to complete the same work?
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Answers

Answered by Anonymous
5

Step-by-step explanation:

Explanation : (A + B)'s 1 day's work =

10

1

C's 1 day's work =

50

1

(A + B + C)'s 1 day's work =

10

1

+

50

1

=

50

6

=

25

3

. .... (i)

A's 1 day's work = (B + C)'s 1 day's work .... (ii)

From (i) and (ii) we get:

2 x (A's 1 day's work) =

25

3

A's 1 day's work =

50

3

.

B's 1 day's work

10

1

-

50

3

=

25

1

So B alone could do the work in 25 days.

I hope it's helpful please mark as brainlist

Answered by Anonymous
1

Answer:

Answer toh mil gaya abb me kya bTauum... xd..

Step-by-step explanation:

hehe

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