A can do 25% of a work in 4 days and B can do one third of the same work in 4 days. C can comp.
work in the same time as A and B would take working together. If all the three work together, how
it take to complete the same work?
Answers
Answered by
5
Step-by-step explanation:
Explanation : (A + B)'s 1 day's work =
10
1
C's 1 day's work =
50
1
(A + B + C)'s 1 day's work =
10
1
+
50
1
=
50
6
=
25
3
. .... (i)
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii) we get:
2 x (A's 1 day's work) =
25
3
A's 1 day's work =
50
3
.
B's 1 day's work
10
1
-
50
3
=
25
1
So B alone could do the work in 25 days.
I hope it's helpful please mark as brainlist
Answered by
1
Answer:
Answer toh mil gaya abb me kya bTauum... xd..
Step-by-step explanation:
hehe
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