Math, asked by jsmsscd, 1 year ago

A can do 3 upon 4 of the work in 15 days and B can do one upon 8 of the work in 5 days in how many days both working together can complete the work​

Answers

Answered by rucha444
1

Answer:

60days

Step-by-step explanation:

A works 3/4 in 15 days

therefore, A = 3/4=15

so, A= 15x4÷3 = 20 days

B works 1÷8 in 5 days

therefore, B = 1/8=5

so, B = 5x8= 40 days

Total days =40+20=60 days

Answered by MavisRee
2

Answer:

A and B together can complete work in 13\frac{1}{3} days

Step-by-step explanation:

A can do \frac{3}{4} of work in 15 days

A can do complete work in 15 \times \frac{4}{3} = 20\hspace{0.1cm}days

Thus, A's 1 day work =\frac{1}{20}

B can do \frac{1}{8} of work in 5 days

B can do complete work in 5 \times \frac{8}{1} = 40\hspace{0.1cm}days

Thus, B's 1 day work =\frac{1}{40}

Total work is LCM of 20 and 40 =40\hspace{0.1cm}parts

A can do parts of work in 1 day =\frac{40}{20} = 2\hspace{0.1cm}parts

B can do parts of work in 1 day =\frac{40}{40} = 1\hspace{0.1cm}parts

(A + B) can do parts of work in 1 day =2 + 1 = 3\hspace{0.1cm}parts

Thus, 3 parts of work (A + B) can do in 1 day

40 parts of work (A + B) can do in \frac{40}{3} = 13\frac{1}{3}\hspace{0.1cm}days

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