A can do 7/8of work in 28days,B can do 5/6 of same work in20 days.the number of days required they work together
Answers
Answered by
0
Answer:
96/7 days
Step-by-step explanation:
work done by a in one day= 7/8/28=1/32
work done by b in one day = 5/6/20=24
work done by both in one day =1/32 + 1/24=7/96
days required=96/7
Similar questions