a can do a certain job in 12 days. B is 60% more efficient than A. Find the number of days
by B to finish the job
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A can do the work in 12 days.
Let us take the total work =1.
Efficiency is work done by time taken. So the efficiency of A = 1/12
B is 60% more efficient than A.
60% of 1/12 = (1/12)*(60/100)=(1/20)
So the efficiency of B = (1/12)+(1/20)
= 2/15=1/7.5
So reciprocal of that gives the no of days =7.5 days
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