a can do a certain job in 12 days .b is 60% more efficient than a. find the number of days taken by b to finish the job.
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Answered by
37
Answer:
7.5 days
Step-by-step explanation:
work done by A in one day = 1/12
Since, B is 60% more efficient than A, thus,
work done by B = 1/12 × 160/100 = 2/15
Therefore, Number days required by B to finish the same work = reciprocal of 2/15 = 15/2 days = 7.5 days
Hope it helps!!
Answered by
14
Step-by-step explanation:
work done by a in one day = 1/12
since ,B is 60%more efficient than aA, this,
work done by B,=1/12×160/100=2/15=15/2= 7.5 day
hence number of days required for B to finish the same work is 7.5 days.
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