Question

a can do a certain job in 12 days .b is 60% more efficient than a. find the number of days taken by b to finish the job.​

Answer 1

Answer:

7.5 days

Step-by-step explanation:

work done by A in one day = 1/12

Since, B is 60% more efficient than A, thus,

work done by B = 1/12 × 160/100 = 2/15

Therefore, Number days required by B to finish the same work = reciprocal of 2/15 = 15/2 days = 7.5 days

Hope it helps!!

Answer 2

Step-by-step explanation:

work done by a in one day = 1/12

since ,B is 60%more efficient than aA, this,

work done by B,=1/12×160/100=2/15=15/2= 7.5 day

hence number of days required for B to finish the same work is 7.5 days.