Math, asked by dhivi04, 1 year ago

a can do a certain job in 12 days b is 60% more effiecent than a.how many days does b alone take to do the same job

Answers

Answered by invisible
1

Since B's efficiency is relative to A , consider B's no. of days to be "x"

1 day work of B = 1/x  ,  1 day work of A = 1/12

So, according to the question, The efficiency of B is =>

(  ( (1/x)-(1/12) )/ (1/12)   ) * 100 =   60  (Since B is 60% more efficient than A)

This would become => ( (12-x)/x)=0.6 => 1.6x = 12 => x= 7.5 days

Similar questions