Question

A can do a certain job in 12 days. B is sixty percent more efficient than a. Find no of days needed by b to finish job

Answer 1

Answer:

7.5 Days

Step-by-step explanation:

A can do a certain job in 12 days

A's 1 day work = $\frac{1}{12}$

B is sixty percent more efficient than a

so

B's 1 day work = A's 1 day work + (60%)of A's 1 day work

B's 1 day work = $\frac{1}{12}$  + ($\frac{60}{100}$ × $\frac{1}{12}$)

B's 1 day work = $\frac{1}{12}$  + $\frac{1}{20}$

B's 1 day work = $\frac{5 + 3}{60}$

B's 1 day work = $\frac{8}{60}$

No of days required by B to complete work

= $\frac{60}{8}$

= 7.5 Days

Answer 2

A can do his job in 12 days
B is 60% more efficient than A
:- B= 60/100*12 => 0.6*12= 7.2 days