A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days. In how many days was the whole work completed?
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Answer:16 2/3 days.
Step-by-step explanation:
LCM of 20,25= 100
A B
25 20
100
4 5 (4+5)=9 /day efficiency
A = 10×4=40
(100-40)=60
60/9= 6 2/3
Total time taken = (10+6 2/3)=16 2/3 days (Ans)
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