Question

A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days. In how many days was the whole work completed?

Answer 1

Answer:16 2/3 days.

Step-by-step explanation:

LCM of 20,25= 100

A B

25 20

100

4 5 (4+5)=9 /day efficiency

A = 10×4=40

(100-40)=60

60/9= 6 2/3

Total time taken = (10+6 2/3)=16 2/3 days (Ans)