A can do a certain job in 25 days which B alone can do in 20 days.a started the work and was joined by b after 10 days in how many days was the whole work completed?
Answers
Answered by
0
Answer:
Work done by A in l0 days = (1/25) *10 = 2/5
Remaining work = 1 - (2/5) = 3/5
(A+B)s 1 days work = (1/25) + (1/20) = 9/100
9/100 work is done by them in 1 day.
hence 3/5 work will be done by them in (3/5)*(100/9)
= 20/3days.
Answered by
0
Your answer is.....
work done by a in 10 days=(1/25)×10=2/5.
remaining work=1-(2/5)=3/5.
(A+B)s. 1 days work=(1/25)+(1/20)=9/100.
9/100 work is done by them in 1 days.
Hence,3/5 work will be done by them in (3/5)×(100/9).
=20 days /3days.
hope it will help you...
mark me as brainliest......
Similar questions