Question

A can do a certain job in 25 days which B alone can do in 20 days.Astarted the work and joined by B after 10 days .ln how many days was the whole work completed?

Answer 1

Answer:

Work done by A in l0 days = (1/25) *10 = 2/5

Remaining work = 1 - (2/5) = 3/5  

(A+B)s 1 days work = (1/25) + (1/20) = 9/100

9/100 work is done by them in 1 day.  

hence 3/5 work will be done by them in (3/5)*(100/9)

= 20/3days.  

Total time taken = (10+20/3)=16*(2/3)days

Step-by-step explanation:

Answer 2

total time taken is 16*(2/3)