A can do a certain job in 25 days which B alone can do it in 20 days . A started the work and was joined by B after 10 days . How many days taken in completing the work .
Answers
Answered by
151
A = 25
B = 20
total work= 100
efficiency of A and B = 4 , 5
A = 10 × 4 = 40 works completed
remaining = 100-40 = 60
remaining work complete by A +B = 60/9 = 20/3 = 6 ⅔ days
again , total work completed in 10 + 6⅔ = 16 ⅔ day will be the answer...
B = 20
total work= 100
efficiency of A and B = 4 , 5
A = 10 × 4 = 40 works completed
remaining = 100-40 = 60
remaining work complete by A +B = 60/9 = 20/3 = 6 ⅔ days
again , total work completed in 10 + 6⅔ = 16 ⅔ day will be the answer...
Answered by
120
Answer:
Step-by-step explanation:
Work done by A in l0 days = (1/25) *10 = 2/5
Remaining work = 1 - (2/5) = 3/5
(A+B)s 1 days work = (1/25) + (1/20) = 9/100
9/100 work is done by them in 1 day.
hence 3/5 work will be done by them in (3/5)*(100/9)
= 20/3days.
Total time taken = (10 + 20/3) = 16*(2/3) days
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