a can do a certain job in 25 days while B can do it in 20 days a started the work and was joined by b after 10 days in how many days was the whole work completed
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The work was done by A in 10 days =10/25=2/5
The remaining work 3/5 completed by A and B together. The number of days required to complete the remaining work =(3/5)/(1/25+1/20)=(3/5)(100/9)=20/3 days.
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