A can do a certain work in 12 days and B can do the same work in 18 days. They worked together for 3
7892
days. The remaining work was completed by B and C working, together, in 3-4 days. C alone will complete
2.
33-% of the whole work in
Answers
Answered by
1
Answer:
Work done by A in 1 day=
12
1
Work done by A in 1 day=
18
1
Work done by A in 1 day=
24
1
Work done by A and B in 1 day=
12
1
+
18
1
Work done by A and B in 3 day=3(
12
1
+
18
1
)
Remaining work=1−3(
12
1
+
18
1
)
=(1−
4
1
+
6
1
)
=
12
7
Work done by B and C in 1 day=
18
1
+
24
1
∴ time taken by B and C to complete the work
=
18
1
+
24
1
1−3(
12
1
+
18
1
)
=
72
4+3
12
7
=
72
7
12
7
=
12×7
7×72
=
12
72
=6 days
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