Question

A can do a certain work in 12 days. B is 60% more efficient than

a. How many days does b alone take to do the same job?

Answer 1

Refer to the attachment !!

Check out all the steps.

The basics are from the Chapter - Work and Time .

Here ,

You have to find the work of B alone.

So , for the solution please refer to the attachment.

Thanks!!

Answer 2

To find,

A's 1 days' work = 1/12

∴ B's 1 days' work = 1.6/12 = 16/120 = 2/15

∴ B shall complete the work in 15/2days =

$7 \frac{1}{2} \: \: days$