A can do a job in 10 days. B can do the same job in 15 days. C can demolish the same job in 20 days. In how many days does the work get completed, if C starts the work and they work on alternate days as C-A-B-C and so on.
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Step-by-step explanation:
A's one day work = 1/10
B's one day work = 1/15
and c's demolish in one day = -1/20 negative the work is destructed
so for every three days work done is = add of all three
i.e 7/60
work done for 24 days(excluding c's first day work where nothing is there to demolish) = 56/60
A will do 4 units in 2/3 days
Total days required=24+2/3+1(first day of job)=25+2/3 days
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