Math, asked by chhayashriavastava67, 4 months ago

A can do a job in 16 days and B can do the same job in 12 days. With the help of C, they can
finish the job in 6 days only. Then, C alone can finish it in​

Answers

Answered by aaravsingh007
1

Answer:

48 days

Step-by-step explanation:

1/6 - (1/12 + 1/16)

1/6 - (1/12 + 1/16)= {8 - (4 + 3)} / 48

1/6 - (1/12 + 1/16)= {8 - (4 + 3)} / 48= 1 / 48

1/6 - (1/12 + 1/16)= {8 - (4 + 3)} / 48= 1 / 48The work done by C in one day = 1 / 48

1/6 - (1/12 + 1/16)= {8 - (4 + 3)} / 48= 1 / 48The work done by C in one day = 1 / 48Time required by C to complete the work alone

1/6 - (1/12 + 1/16)= {8 - (4 + 3)} / 48= 1 / 48The work done by C in one day = 1 / 48Time required by C to complete the work alone= 48 days

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