Math, asked by ashishkumar8430, 3 days ago

A can do a job in 16 days and B can do the same job in 12 days. With the help of C, they can finish the job in 6 days only. Then, C alone can finish it in​

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Answered by bhavinparicherla
1

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>>A can do a job in 16 days and B can do t

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A can do a job in 16 days and B can do the same job in 12 days With the help of C, they can finish the job in 6 days only. Then, C alone can finish it in

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Correct option is D)

We know that,

Number of days A requires to do piece of work =16 days

Number of days B requires to do piece of work =12 days

Let us consider number of days C requires to do piece of work =x days

Number of days A,B and C together requires to do the piece of work =6 days

∴ We can calculate, work done by A in 1 day =1/16

Work done by B in 1 day =1/12

Work done by C in 1 day =1/x

Work done by A,B and C together in a 1 day =1/6

Now, work done by A,B and C together in 1 day is also equal to the sum of work done by each of them in 1 day =1/16+1/12+1/x=7/48+1/x

Therefore,

7/48+1/x=1/6

(7x+48)/48x=1/6

42x+288=48x

6x=288

x=288/6=48

∴C can do the work in 48 days.

Step-by-step explanation:

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