Question

A can do A job in 16 days and B can do the same work in 12 days. with the help of C, they can finish the job in 6 days only.Then C alone can finish it in how many days ?​

Answer 1

Answer:

A's one day's work =1/16

B's one day's work =1/12

A+B 's one day's work =1/16+1/12=7/48

A+B+C's one day's work = 1/6

C's one day's work = 1/6 - 7/48 = 1/48

C will take 48 days to complete the work .

Answer 2

Step-by-step explanation:

a can do work in one day = 1/16

b can do work in one day = 1/12

with c they can work in one day = 1/6

a and b 's work in one day = 1/16+1/12=7/48

(a+b+c )'s one day work - (a+b)'s one day work = 1/6-7/48 = 1/48

1/48= c 's alone work in one day

c can do whole work in 48 days