A can do a job in 20 days, B in 30 days and C in 60 days.If B And C help A on the third day,in how long that work be completed?
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Answer:
A - 20 days
B- 30 days
C- 60 days
let LCM = 60 is total work
then A = 20*3 units/day
B = 30*2 units/day
C = 60*1 unit/day
for 4 days A only can do = 4*3 = 12 units
3 rd day B also joins with 2 units
4th day C also joins with 1 unit/day
at the end of 4 day total work done = 12+2+1 = 15 units
4 days = 15 units
4*4 days = 15*4 units
16 days = 60 units = total work completed
Step-by-step explanation:
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