Math, asked by manjarivishwakarma1, 3 months ago

a can do a job in 20 days b in 30 days and c is 60 days if a is held by b and c on every third day then in how many days will the job be finished​

Answers

Answered by prasanthikuchipudi
0

Answer:

20 days

Step-by-step explanation:

a,b,c can do in 20,30,60

LCM is 60 = 60p

a can complete in 60p/20=3p

b can complete in 60p/30=2p

c can complete in 60p/60=1p

a has to do for first 2 days:

              3p=1day

              6p=2days

b and c in third day

              2p+1p=>3p=1 day

total 9 p for 3 days

      54 p for 18 days

remaining 6p for a,b,c 2days

total 54p+6p=>60 p

      18+2=20days

Answered by nimbuskumar14
0

Answer:

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