Question

A can do a job in 26 days. B is 30% more efficient than A. In how many days can B alone do the same job?
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Answer 1

Answer:

B.13 days

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Answer 2

The number of days taken by B alone do the same job is 20 days.

Step-by-step explanation:

Given:

A can do a job in 26 days.

B is 30% more efficient than A.

To Find:

The number of days taken by B alone do the same job.

Formula Used:

If  a man completes work in p days.

Work done in 1 day = 1/p part of the work.

Solution:

As given-B is 30% more efficient than A.

The ratio of number of days taken by A to B $= 130:100$

                                                                           $=13:10$

Let B takes K number of days.

$26:K: \ : 13:10$

 $\frac{26}{K} =\frac{13}{10}$

$13K=26\times10$

$13K=260$

$K=20\ days$

Thus,the number of days taken by B alone do the same job is 20 days.

PROJECT CODE#SPJ3