Question

a can do a job in 60 days while A and B can do it together in 2 days how many days will be taken by B to do the job alone​

Answer 1

Solution :

A can do a job in 60 days

So, work done by A in 1 day = 1/60

A and B can do it in 2 days

So, work done A and B in 1 day = 1/2

We know that

Work done by B in 1 day = Work done by A and B in 1 day - Work done by A in 1 day

= 1/2 - 1/60

Taking LCM

= (30 - 1)/60

= 29/60

i.e Work done by B in 1 day = 29/60

⇒ B can do it in 60/29 = 2 days (approx )

Hence, B alone can do it in 2 days.

Answer 2

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a can do a job in 60 days while A and B can do it together in 2 days how many days will be taken by B to do the job alone?

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A can do a job in 60 days

So, work done by A in 1 day = 1/60

A and B can do it in 2 days

So, work done A and B in 1 day = 1/2

We know that

Work done by B in 1 day = Work done by A and B in 1 day - Work done by A in 1 day

→ 1/2 - 1/60

So , by Taking LCM

→ (30 - 1)/60

→29/60

→ Work done by B in 1 day = 29/60

→ B can do it in 60/29 = 2 days (approximately )