Math, asked by rs07122013, 3 days ago

A can do a particular work in 25 days,B can do it in 20 days if they work individually they work together for 5 days and then B lives and how many day will finish the remaining task.​

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Answered by udgirkar67
2

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Class 11

>>Applied Mathematics

>>Numerical Applications

>>Time and work

>>A can do a piece of work in 25 days and

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A can do a piece of work in 25 days and B in 20 days. They work together for 5 days and then A goes away. In how many days will B finish the remaining work?

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Solution

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Correct option is B)

A's 1 day's work =

25

1

Similarly, B's 1 day's work =

20

1

A's and B's together 1 day's work

25

1

+

20

1

=

100

4

+

100

5

=

100

4+5

=

100

9

Their 5 day's work together = 5 x 1 day's work

1−

100

45

=

100

100

100

45

=

100

100−45

=

100

55

Now, this remaining work is done by B.

Let B takes x days to complete it.

20

1

×x=

100

55

⇒x=

100

55

×20

⇒x=

5

55

⇒x=11

Hence, B will finish the remaining work in 11 days.

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