A can do a Peice of work in 20 days and B can do peice of work in 30 days if they work together for 3 days and then B leaves how many does will A finish the remaining work?
Answers
Answered by
0
Answer:
24 days they finish the remaining work
Answered by
41
Answer:
Given A can do the work in 20 days and B can do it 15 days.
Then work done by A in one day
=
20
1
And, work by B in one day
=
15
1
Then, the work done by A & B in one day
=
20
1
+
15
1
=
60
7
A & B done 6 days together then work done in A & B in 6 days
=
60
7
×
6=
10
7
Then friction of work left
=
1−
10
7
=
10
3
Then B can do
10
3
work =
10
3
×
1
15
=
2
9
=
4
2
1
days.
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