A can do a peice of work in 9 days, B in twice that time, C can do only 3/4 as much as A in a day, how long would A, B, C working together required to do the same pieceof work
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Step-by-step explanation:
time taken by a =9
time taken by b=18
time taken by c=27/4
work a does in 1 day =9
work b does in 1 day=18
work c does in 1 day=4/27
how much work all complete in 1 day = 1/9+1/18+4/27
=(3+2+4)/27
=9/27
=1/3
days taken =3 days because 1/3 work completed in 1 day
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