A can do a picece of work in 30 days and b can do same work in 60 days in how many days a and b complete the work
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Answer:
A's one day work = 1/30
B's one day work= 1/60
(A+B)'s one day work= 1/30 + 1/60
Find the LCM It's 60
1/30 * 2/2 + 1/60 = 2/60 + 1/60 = 3/60
total day required = 1 / 3/60 = 1 × 60/3 = 20
and b together can complete the work in 20 days
hope it helps you
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