Question

a can do a piece of a work 12 days and B alone can do it in 16 days.They worked together on it for 3days can then A left.How long did B take to finish the remining work​

Answer 1

Answer:

8 days

Step-by-step explanation:

Average work=48(LCM of 16 and 12)

A does 48 work in 16 days

In 1 day 48/16=3work

B does 48 work in 12 days

In 1 day 48/12=4work

A done work for 2 days

So,work done by A 8n 2 days=2×3=6

Remaining work is 42

A+B together can do 7 work in a day

Thus,42/7=6days

Total days 6+2=8days

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