a can do a piece of a work 12 days and B alone can do it in 16 days.They worked together on it for 3days can then A left.How long did B take to finish the remining work
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Answer:
8 days
Step-by-step explanation:
Average work=48(LCM of 16 and 12)
A does 48 work in 16 days
In 1 day 48/16=3work
B does 48 work in 12 days
In 1 day 48/12=4work
A done work for 2 days
So,work done by A 8n 2 days=2×3=6
Remaining work is 42
A+B together can do 7 work in a day
Thus,42/7=6days
Total days 6+2=8days
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ashwini5146:
but answer is 9days
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