Question

A can do a piece of job in 24 days, while B can do that job in 30 days. A. B and C togethercan do the job in 12 days. In how much time can C do the job alone In 120 days . If they are paid 5000. find their shares.​

Answer 1

$[tex]work \: done \: by \: a \: in \: 1 \: day \: = \: \frac{1}{24}$

$work \: done \: by \: b \: in \: 1 \: day \: = \: \frac{1}{30}$

$let \: work \: done \: by \: c \: in \: one \: day \: = \: \frac{1}{c}$

$together \: they \: do \: \frac{1}{12} \: in \: one \: day$

$\frac{1}{24} + \frac{1}{30} + \frac{1}{c} = \frac{1}{12}$

$c \: = 120 \: days$

$\frac{1}{24} \: \frac{1}{30} \: \frac{1}{120}$

$shares$

$a \: = \frac{1}{4} \times 5000 = 1250$

$b \: = \frac{1}{5} \times 5000 = 1000$

$c \: = \frac{1}{20} \times 5000 = 250$

[/tex]

Hence proved

Thanks