Question

A can do a piece of work at 10 days how long will it take by B To do same work if hi is half slow as A

Answer 1

Answer:

A ' s one day work will be , 1/ 10

B is half efficient of A, so he will do it in 1/10 ×1/2 = 1/20

so now We know B's one day work we can find that in how many time he will do the work

1/20 reciprocal = 20 days

Answer 2

Answer :-

B can do the same work in 20 days

Solution :-

A can do a piece pf work in 10 days

So A's one day work = 1/10

Given

B can do it and he works half slow as A

So B is half efficient of A

B's one day work = Half of A's one day work

= 1/2 * 1/10

= 1/20

B's one day work = 1/20

So B can do the sane work in 20 days.