A can do a piece of work in 10 days and B can do it 15 days if both of them are working together, how many days will be required to complete half the work
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Answer:
3days
Step-by-step explanation:
A can do a peice of work in 10days
B can do a peice of work in 15 days
total work = LCM OF 10 AND 15
total work = 30
efficiency of A is 30÷ 10= 3
efficiency of B is 30÷15 = 2
total efficiency of both = 3 + 2 = 5
half of the work = 30÷2
15
therefore,
days required to complete half of the work if they work together = work ÷ total efficiency
= 15÷ 5 = 3 days
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