Question

A can do a piece of work in 10 days and B can do it in 12 days. They work together for 3 days, then B leaves and A alone continues. 2 days after that, C joins and the work is completed in 2 days more. In how many days can C do it if he works alone? ​

Answer 1

Given that : A can do a piece of work in 10 days and B can do it in 12 days.

Let, Total work = LCM of 10 and 12 = 60

Then, One day work of A = 6 and one day work of B = 5

Now, they work together for 3 days

So, the complete the work = 3×(5+6) = 33

Remaining work = 60 - 33 = 27

A works alone for 2 days so he completed the work in 2 days = 2×6 = 12

Now, remaining work = 27-12 = 15

After 2 days work is completed with the partnership of C.

According to the question : 2×A + C = 15

=> 2×6 + C = 15

=> 12 + C = 15

=> C = 15 - 12 = 3

Thus, work of C of 2 days = 3

One day work of C = 3/2 = 1.5

So, C will complete the total work = 60/1.5 = 40

Thus, C will complete the total work in 40 days.

I hope it will be helpful for you ✌️✌️

Mark it as brainliest and

Fóllòw MË ☺️☺️