Question

A can do a piece of work in 10 days and B can do it in 15 days. The number of days required by them to finish it, working together is:

Answer 1

Step-by-step explanation:

A 10days

B 15days

time required= 1/10+1/15

3+2/30

5/30= 1/6

reciprocal = 6 days

Answer 2

Answer:

6 days

Sᴏʟᴜᴛɪᴏɴ

Given.

A can finish the work in D¹ = 10 days

B can finish the work in D² = 15 days

If A and B working together

So formula used is

$\frac{d1 \times d2}{d1 + d2}$

Putting the above values in this formula

$\frac{10 \times 15}{10 + 15}$

$\frac{150}{25} = 6days$

So , from above we conclude that

if a and b work together they finish the work in 6 days